Question

log1/2(2x-5)>-1
помогите пожалуйста

Answer 1

{2x-5>0⇒2x>5⇒x>2,5
{2x-5<2⇒2x<7⇒x<3,5
x∈(2,5;3,5)

Answer 2

$log_{frac{1}{2}}(2x-5) textgreater -1 textless = textgreater log_{frac{1}{2}}(2x-5) textgreater log_{frac{1}{2}}2$

ОДЗ: 
$2x-5 textgreater 0\2x-5 textless 2$

$2 textgreater 2x-5 textgreater 0\7 textgreater 2x textgreater 5\3,5 textgreater x textgreater 2,5$
\\α//////β//////////c///
––|––––––––––––>
где $alpha=0$, $beta=2,5$, $c=3,5$.
x∈(2,5; 3,5)