Question

помогите! log3(x-3)<1

Answer 1

$log_3(x-3) textless 1 textless = textgreater log_3(x-3) textless log_33$

Решение:
ОДЗ: 
$x-3 textgreater 0\x-3 textless 3$

$3 textgreater x-3 textgreater 0\6 textgreater x textgreater 3$
Ответ: x∈(3; 6)