Question

AL2C3-->CH4-->C2H2-->CH3COH-->CH3COOH--->CH3COOC3H7

Answer 1

1)AL4C3+12H2O=
=4AL(OH)3+3CH4
2)2CH4=C2H2+3H2
(1500°,кат.)
3)C2H2+H2O=CH3COH
(кат.)
4)CH3COH+Ag2O=
=CH3COOH+2Ag
(аммиачный раствор)
5)CH3COOH+C3H7OH=
=CH3COOC2H7+H2O
(кат.)