Question

8sin(3x+pi/4)-4=0.помогите

Answer 1

$8sin(3x+ frac{ pi }{4} )-4=0, sin(3x+ frac{ pi }{4} )= frac{1}{2}$
$3x+ frac{ pi }{4}=(-1) ^{n} *arcsin frac{1}{2}+ pi n, n$∈Z

$3x=(-1) ^{n} * frac{ pi }{6} - frac{ pi }{4}+ pi n, n$∈Z

$x=(-1) ^{n} * frac{ pi }{18} - frac{ pi }{12} + frac{ pi n}{3} , n$∈Z