Question

Помогите решить пример

Answer 1

1/[(x-y)(x-z)]-1/[-(x-z)*(-(x-y))]=1/[(x-y)(x-z)]-1/[(x-y)(x-z)]=0

Answer 2

1/ ((x-y)(x-z))    -   1/ ((z-х)(у-х))  = 
= 1/ ((х-у)(x-z) )   -  1/ ( -(x-z) *  -(x-y)) =
= 1/ ((x-y)(x-z))  -    1/ ((x-y)(x-z))=0