Question

решите уравнение (x^2-x+2)^2-3(x^2-x+3)=1

Answer 1

x²-x+2=a
a²-3(a+1)-1=0
a²-3a-4=0
a1+a2=3 U a1*a2=-4
a1=4⇒x²-x+2=4
x²-x-2=0
x1+x2=1 U x1*x2=-2
x1=-1 U x2=2
a2=1⇒x²-x+2=1
x²-x+1=0
D=1-4=-3<0 tn htitybz