Question

решите уравнения 1) x^2+3x-(1-2x^2)=3x^2-x+4 2) x^2-5x+5=-x^2-x-(-3-2x^2) 3)-2x^2+4x-7=-x^2+2x-(x^2-3)

Answer 1

N 1
X^2 + 3x - ( 1 - 2x^2 ) = 3x^2 - x + 4
X^2 - 3x - 1 + 2x^2 = 3x^2 - X + 4
3x^2 - 3x - 1 = 3x^2 - X + 4
- 3x + X = 4 + 1
- 4x = 5
X = - 1,25
ОТВЕТ ( - 1,25 )
N 2
X^2 - 5x + 5 = - x^2 - x - ( - 3 - 2x^2 )
X^2 - 5x + 5 = - x^2 - X + 3 + 2x^2
X^2 - 5x + 5 = x^2 - X + 3
- 5x + X = 3 - 5
- 4x = - 2
X = 0,5
ОТВЕТ 0,5
N 3
- 2x^2 + 4x - 7 = - x^2 + 2x - ( x^2 - 3 )
- 2x^2 + 4x - 7 = - x^2 + 2x - x^2 + 3
- 2x^2 + 4x - 7 = - 2x^2 + 2x + 3
4x - 2x = 3 + 7
2x = 10
X = 5
ОТВЕТ 5