Question

решить неравенство 7x-3/5x-4≤1

Answer 1

7x-3/5x-4=0
7x-3=0×5x-4
7x-3=0
7x=3
x=3/7
(7×3/7-3)/(5*3/7-4)=
=(28/7-3)/(15/7-4)=
=(3-3)/(15/7-4)=
0/(15/7-4)=0
0<1
ответ: 3/7