Question

Решите уравнение 4x^2-x-3=0

Answer 1

$4 x^{2} -x-3=0 \ D=b^2-4ac=1+48=49 \ x_{1} = frac{-b+ sqrt{D} }{2a} = frac{1+7}{8} =1 \ x_{2} = frac{-b- sqrt{D} }{2a} = frac{1-7}{8} =-0.75$

Answer 2

Благодарю!