Question

Решите систему неравенств.

2х + 4 ≥ 0,
15 - 3х ≤ 0.

Answer 1

$left { {{2x+4 geq 0} atop {15-3x leq 0}} right. left { {{2x geq -4} atop {-3x leq -15}} right. left { {{x geq -2} atop {x geq 5}} right.$
x∈[5;+∞)
Ответ: [5; +∞)