Question

Решить уравнение************

Answer 1

$10cdot 5^{x^2+4x+1}-0,4=0; ,; ; ; ; ODZ:; xin R\\5^{x^2+4x+1}=0,04\\ 0,04= frac{4}{100} = frac{1}{25} =frac{1}{5^2}=5^{-2}\\5^{x^2+4x+1}=5^{-2}\\x^2+4x+1=-2\\x^2+4x+3=0\\x_1=-3; ,; x_2=-1; ; (teorema; Vieta)$