Ответы
Ответ дал:
0
Произведение будет меньше равно нуля, если либо первый множитель ≥ 0 и второй множитель ≤0, либо наоборот.
![displaystyle left[begin{array}{ccc}begin{cases}
& text{ } begin{cases}
& text{ } x-1 textgreater 0 \
& text{ } x+2 geq 1
end{cases}\
& text{ } begin{cases}
& text{ } x+2 textgreater 0 \
& text{ } x+2 leq 1
end{cases}
end{cases}
\ begin{cases}
& text{ } begin{cases}
& text{ } x-1 textgreater 0 \
& text{ } x-1 leq 1
end{cases} \
& text{ } begin{cases}
& text{ } x+2 textgreater 0 \
& text{ } x+2 geq 1
end{cases}
end{cases}end{cases}end{array}right~~~Rightarrow displaystyle left[begin{array}{ccc}begin{cases}
& text{ } begin{cases}
& text{ } x-1 textgreater 0 \
& text{ } x+2 geq 1
end{cases}\
& text{ } begin{cases}
& text{ } x+2 textgreater 0 \
& text{ } x+2 leq 1
end{cases}
end{cases}
\ begin{cases}
& text{ } begin{cases}
& text{ } x-1 textgreater 0 \
& text{ } x-1 leq 1
end{cases} \
& text{ } begin{cases}
& text{ } x+2 textgreater 0 \
& text{ } x+2 geq 1
end{cases}
end{cases}end{cases}end{array}right~~~Rightarrow](https://tex.z-dn.net/?f=displaystyle+++left%5Bbegin%7Barray%7D%7Bccc%7Dbegin%7Bcases%7D%0A+%26amp%3B+text%7B++%7D+begin%7Bcases%7D%0A+%26amp%3B+text%7B++%7D+x-1+textgreater++0+%5C+%0A+%26amp%3B+text%7B++%7D+x%2B2+geq+1+%0Aend%7Bcases%7D%5C+%0A+%26amp%3B+text%7B++%7D+begin%7Bcases%7D%0A+%26amp%3B+text%7B++%7D+x%2B2+textgreater++0+%5C+%0A+%26amp%3B+text%7B++%7D+x%2B2+leq+1+%0Aend%7Bcases%7D+%0Aend%7Bcases%7D%0A%5C+begin%7Bcases%7D%0A+%26amp%3B+text%7B++%7D+begin%7Bcases%7D%0A+%26amp%3B+text%7B++%7D+x-1+textgreater++0+%5C+%0A+%26amp%3B+text%7B++%7D+x-1+leq+1+%0Aend%7Bcases%7D+%5C+%0A+%26amp%3B+text%7B++%7D+begin%7Bcases%7D%0A+%26amp%3B+text%7B++%7D+x%2B2+textgreater++0+%5C+%0A+%26amp%3B+text%7B++%7D+x%2B2+geq+1+%0Aend%7Bcases%7D+%0Aend%7Bcases%7Dend%7Bcases%7Dend%7Barray%7Dright%7E%7E%7ERightarrow)
![left[begin{array}{ccc}begin{cases}
& text{ } x textgreater 1 \
& text{ } -2 textless x leq -1
end{cases}\begin{cases}
& text{ } 1 textless x leq 2 \
& text{ } x geq -1
end{cases}end{array}right~~~Rightarrow~~~ 1 textless x leq 2 left[begin{array}{ccc}begin{cases}
& text{ } x textgreater 1 \
& text{ } -2 textless x leq -1
end{cases}\begin{cases}
& text{ } 1 textless x leq 2 \
& text{ } x geq -1
end{cases}end{array}right~~~Rightarrow~~~ 1 textless x leq 2](https://tex.z-dn.net/?f=++left%5Bbegin%7Barray%7D%7Bccc%7Dbegin%7Bcases%7D%0A+%26amp%3B+text%7B++%7D+x+textgreater++1+%5C+%0A+%26amp%3B+text%7B++%7D+-2+textless++x+leq+-1%0Aend%7Bcases%7D%5Cbegin%7Bcases%7D%0A+%26amp%3B+text%7B++%7D+1+textless++x+leq+2+%5C+%0A+%26amp%3B+text%7B++%7D+x+geq+-1%0Aend%7Bcases%7Dend%7Barray%7Dright%7E%7E%7ERightarrow%7E%7E%7E+1+textless++x+leq+2)
Вас заинтересует
1 год назад
6 лет назад
6 лет назад
8 лет назад
8 лет назад
9 лет назад