Question

найдите целочисленные решения неравенства

Answer 1

$frac{2x}{5-x^2} leq frac{2x-x^2}{x^2-5} ; ,; ; ODZ:; ; x^2ne 5; ,; ; xne pm sqrt5\\ frac{2x}{5-x^2} + frac{2x-x^2}{5-x^2} leq 0\\ frac{4x-x^2}{5-x^2} leq 0\\ frac{x(x-4)}{(x-sqrt5)(x+sqrt5)} leq 0\\+++(-sqrt5)---[, 0, ]+++(sqrt5)---[, 4, ]+++\\xin (-sqrt5,0, ]cup (sqrt5,4, ]$