Question

найти производную в точке x=-2,5 $( x^{3} +6x^2+12x+9)/x+2$

Answer 1

[(x³+6x²+12x+9)/(x+2)]`=[(3x²+12x+12)(x+2)-(x³+6x³+12x+9)]/(x+2)²=
=(3x³+6x²+12x²+24x+12x+24-x³-6x²-12x-9)/(x+2)²=
=(2x³+12x²+24x+3)/(x+2)²
x=2,5
(31,25+75+60+3)/20,25=169,25/20,25=8 29/81