Question

67^2-33^2:(27^2+46*27+23^2)

Answer 1

$(67^2-33^2):(27^2+46*27+23^2)= \ =(67-33)*(67+33):(27^2+2*27*23+23^2)= \ =34*100:(27+23)^2=34*100:50^2=34*2:50=68:50= \ =136:100=1,36$

Answer 2

27^2+46*27+23^2=
27^2+2*27*23+23^2=
(27+23)^2=50^2

67^2-33^2=(67-33)*(67+33)=34*100

34*2*50:50^2=34*2:50=34:25=1.36