Question

РЕБЯТКИ, ПОМОГИТЕ ОЧЕНЬ СРОЧНООО!!!!!!
Решите уравнение

Answer 1

3 - ( 4^2x - 1) = ( 17 - 2•4^2x ) ^ 0,5
4 ^ 2x = a
3 - 0,25a = ( 17 - 2a )^0,5
( 3 - 0,25a )^2 = 17 - 2a
9 - 1,5a + 0,0625a^2 = 17 - 2a
0,0625a^2 + 0,5a - 8 = 0
0,5( 0,125a^2 + a - 16 ) = 0
D = 1 + 8 = 9 = 3^2
a1 = ( - 1 + 3 ) : 0,25 = 8
a2 = ( - 1 - 3 ) : 0,25 = - 16 ( < 0 )
4 ^ 2x = 8
2 ^ 4x = 2 ^ 3
4x = 3
X = 0,75

Answer 2

$sqrt{A}=B; left { {{A=B^2} atop {B geq 0}} right.$
пусть $t= 4^{2x} textgreater 0,$
$left { {{17-2t=(3- frac{t}{4} )^2} atop {3- frac{t}{4} } geq 0} atop t geq 0 right., left { {t^2-8t-128=0} atop { 0leq t leq 12}} right. , left { {{t=-4; t=8}} atop { 0leq t leq 12}} right. , t=8$
$4^{2x}=8; 2^{4x}=2^3; x=3/4.$