Question

Линейная функция задана формулой у=кх+b
как найти к, если у(2)=1 и у(-3)=11?

Answer 1

$left { {{1=kcdot2+b} atop {11=kcdot(-3)+b}} right. \ -left { {{2k+b=1} atop {-3k+b=11}} right. \ left { {{2k-(-3k)=1-11} atop {-3k+b=11}} right. \ left { {{2k+3k=-10} atop {b=11+3k}} right. \ left { {{5k=-10} atop {b=11+3k}} right. \ left { {{k=-2} atop {b=11+3cdot(-2)}} right. \ left { {{k=-2} atop {b=5} right. \ y=-2x+5$

Answer 2

1 = 2k + b
11 = - 3k + b
Решение
- 1 = - 2k - b
10 = - 5k
k = - 2