Question

Реши неравенства
а)0,3(2m-3)<3(0,6m+1,3)
б)1,1(5x-4)>0,2(10х-43)

Answer 1

а) 
$0,3(2m-3) textless 3(0,6m+1,3)\0,6m-0,9 textless 1,8m+3,9\12m textgreater -48\m textgreater -4$
m∈(–4; +∞)
б) 
$1,1(5x-4) textgreater 0,2(10x-43)\55x-44 textgreater 20x-86\35x textgreater -42\x textgreater -frac{6}{5}$
x∈(–1,2; +∞)