Question

Сократите дробь:
b^12+b^6+1/b^18-1

Answer 1

b⁶=x
b¹²=(b⁶)²=x²
b¹⁸=(b⁶)³=x³

(x²+x+1)/(x³-1)=(x²+x+1)/((x-1)(x²+x+1))=1/(x-1)=1/(b⁶-1)