Question

найдите корни уравнения 9х^2-10х+1=0

Answer 1

D = b^2-4ac = 100-4*9*1 = 100-36 = 64
x1 = (-b + √D)/2a = (10+8)/18 = 1
x2 = (-b-√D)/2a = (10-8)/18 = 1/9