Question

Решите неравенство:

|1-x²|<(1-x)²

Answer 1

xyy'=1-x²
yy'=(1-x²)/x
yy'=1/x-x
∫yy' dx=∫1/x-x dx
∫y dy=ln|x|-x²/2 +C1
y²/2=ln|x|-x²/2 +C1
y²=2ln|x|-x² +C