Question

x^3 + 2x^2 - 4x - 8=0

Answer 1

x³ + 2x² - 4x - 8 =x²(x+2)-4(x+2) = (x²-4)(x+2)= (x-2)(x+2)(x+2) =(x-2)(x+2)² = 0

ответ: -2 и 2