Question

(x^2-6x+1)^2+6(x^2-6x+1)-7=0 помогите

Answer 1

Пусть x^2 - 6x + 1 = t, тогда
t^2 + 6t - 7 = 0 
D = 36 + 28 = 64 = 8^2
t1 = ( - 6 + 8)/2 = 1
t2 = ( - 6 - 8)/2 = - 7

Возвращаемся обратно к замене
1) x^2 - 6x + 1 = 1
x^2 - 6x = 0 
x (x - 6) = 0 

x1 = 0 ;
x2 = 6

2) x^2 - 6x + 1 = - 7
x^2 - 6x + 8 = 0 
D = 36 - 32 = 4 = 2^2
x3 = ( 6 + 2)/2 = 4
x4 = ( 6 - 2)/2 = 2

Ответ
4; 2; 0; 6