Question

(169^3+59^3)/228-169*59

Answer 1

$<var>\frac{169^3+59^3}{228}-169*59 = \frac{(169+59)(169^2-169*59+59^2)}{228}-169*59 =</var>$

 

$<var>\frac{228(169^2-169*59+59^2)}{228}-169*59 = 169^2-169*59+59^2-169*59 = \\\\169^2-2*169*59+59^2 = (169-59)^2 = 110^2 = 12100</var>$

 

Использовали формулу: $<var>a^3 + b^3 = (a+b)(a^2-ab+b^2)</var>$