Question

2sin^3x-3tg4x-4 Найдите производную

Answer 1

(2sin3x-3tg4x-4)' = (2sin3x)' - (3tg4x)' - (4)' =
2(sin3x)' - 3(tg4x)' = 2 cos 3x * (3x)' - 3*[1/cos^2(4x) ] * (4x)' =
6 cos 3x - 12/ cos^2(4x)