Question

решите систему уравнений
заранее спасибо

Answer 1

$left { {{ x^{2} -3 y^{2} =24} atop {x+y=8}} right. left { {{(8-y)- 3y^{2} =24} atop {x=8-y}} right. \ (8-y)-3 y^{2} -24=0 \ 64-16y+ y^{2} -3 y^{2} -24=0 \ 40-16y-2 y^{2} =0 \ 20-8y- y^{2} =0 \ D=8 ^{2} -4*20*(-1)=144= x=12^{2} \ y_{1} =0.5 \ y_{2} =-0.1 \ x_{1} -8-0.5=7.5 \ x_{2} =8-(-0.1)=8.1$