Ответы
Ответ дал:
0
5x( x-y) / x^3 (y-x)
![frac{-5x(y-x)}{ x^{3}(y-x) } =- frac{5}{ x^{2} } frac{-5x(y-x)}{ x^{3}(y-x) } =- frac{5}{ x^{2} }](https://tex.z-dn.net/?f=+frac%7B-5x%28y-x%29%7D%7B+x%5E%7B3%7D%28y-x%29+%7D+%3D-+frac%7B5%7D%7B+x%5E%7B2%7D+%7D+)
3a-36/ 12b- ab
![frac{3(a-12)}{b(12-a)} = frac{-3(12-a)}{b(12-a)} =- frac{3}{b} frac{3(a-12)}{b(12-a)} = frac{-3(12-a)}{b(12-a)} =- frac{3}{b}](https://tex.z-dn.net/?f=+frac%7B3%28a-12%29%7D%7Bb%2812-a%29%7D+%3D+frac%7B-3%2812-a%29%7D%7Bb%2812-a%29%7D+%3D-+frac%7B3%7D%7Bb%7D+)
8b^2-8a^2 / a^2-2ab + b2
![frac{8( b^{2} - a^{2} )}{(a-b)^{2} } = frac{8(b-a)(b+a)}{(a-b)(a-b)} = frac{-8(a-b)(b+a)}{(a-b)(a-b)} = - frac{8b+a}{a-b} frac{8( b^{2} - a^{2} )}{(a-b)^{2} } = frac{8(b-a)(b+a)}{(a-b)(a-b)} = frac{-8(a-b)(b+a)}{(a-b)(a-b)} = - frac{8b+a}{a-b}](https://tex.z-dn.net/?f=+frac%7B8%28+b%5E%7B2%7D+-+a%5E%7B2%7D+%29%7D%7B%28a-b%29%5E%7B2%7D+%7D+%3D+frac%7B8%28b-a%29%28b%2Ba%29%7D%7B%28a-b%29%28a-b%29%7D+%3D++frac%7B-8%28a-b%29%28b%2Ba%29%7D%7B%28a-b%29%28a-b%29%7D+%3D+-+frac%7B8b%2Ba%7D%7Ba-b%7D+)
3a-36/ 12b- ab
8b^2-8a^2 / a^2-2ab + b2
Вас заинтересует
1 год назад
1 год назад
6 лет назад
8 лет назад
8 лет назад
9 лет назад