Question

Задание 359. Выполните действие

Answer 1

$1)(2^2) ^{10} *(2^4)^3/((2^2)^2*(2^2) ^{12} )=2 ^{20}*2 ^{12} /(2^4*2 ^{24})=$$2 ^{20+12-2-24} =2^4=16$
$2)((6^5)^4:(6^4)^2)/(6*(6^2)^5)=(6 ^{20} :6^8)/(6*6 ^{10} )=6 ^{12} /6 ^{11} =6$
$3)((5^3)^6:5)/((5^4)^3*5^2)=(5 ^{18} :5)/(5 ^{12} *5^2)=5 ^{17}/5 ^{14} =5^3=125$
$4)(3^8)^3*3^5/((3^2) ^{10} *(3^4)^2)=3 ^{24}*3^5/(3 ^{20} *3 ^{8} )=$$3 ^{29}/3 ^{28} =3$