Question

Решите уравнение плз !! (y+2)(3y-9)=0

Answer 1

(y+2)(3y-)=0
Y+2=0-(3y-9)
Y=3
(3+2)*(3*3)=0

Answer 2

(y+2)(3y-9)=0
3y²-9y+6y-18=0
3y²-3y-18=0
Д=(-3)²-4×3×(-18)=9+216=225
y₁=$\frac{3+ \sqrt{225} }{2*3}$=$\frac{3+15}{6}$=$\frac{18}{6}$=3
y₂=$\frac{3-15}{6}$=$\frac{-12}{6}$=-2