Question

найти предел функции

Answer 1

3/(1-x^3) + 1/(x-1) =
-3/(x-1)(1+x+x^2) + 1/(x-1) =
-3/(x-1)(1+x+x^2) + (1+x+x^2)/(x-1)(1+x+x^2) =
(x^2+x-2)/(x-1)(1+x+x^2) =
(x+2)(x-1)/(x-1)(1+x+x^2) =
(x+2)/(1+x+x^2) -> 3/3 = 1