Question

(x-5)^2=(x-3)^2 помогите решить

Answer 1

Вот. решение в фото.....................

Answer 2

$(x-5)^{2} - (x-3)^{2} = 0$
$(x-5-(x-3))*(x-5+x-3)=0$
$(x-5-(x-3))*(2x-5-3)=0$
$(x-5-(x-3))*(2x-8)=0$
$(x-5-x+3)*(2x-8)=0$
$(0-5+3)*(2x-8)=0$
$(-5+3)*(2x-8)=0$
$(-2)*(2x-8)=0$
$-2*2x+2*8=0$
$-4x+2*8=0$
$-4x+16=0$
$-4x=-16$
$x=4$