Question

l 3x-2 l +5=7           l 5x+3 l -3=0
Модуль 3х-2 +5=7   Модуль 5х+3  -3=0

Answer 1

log 5 (7-x) = log 5 (3-x) + 1
log 5 (7-x) = log 5 (3-x) + log 5 (5)
log 5 (7-x) = log 5 [5*(3-x)]
7-x = 5*(3-x)
7-x = 15 - 5x
5x = 8
x = 5/8