Question

Решите пример срочного

Answer 1

$frac{b-c}{b} - frac{c^2}{b^2-bc} + frac{2b}{b-c} = frac{b-c}{b} -frac{c^2}{b(b-c)} + frac{2b}{b-c} = frac{(b-c)(b-c)-c^2+2b^2}{b(b-c)} =$$frac{b^2-2bc+c^2-c^2+2b^2}{b(b-c)} = frac{3b^2-2bc}{b(b-c)} =$$frac{b(3b-2c)}{b(b-c)} = frac{3b-2c}{b-c}$