Question

Представьте в виде дроби

Answer 1

1)6x/(x-2)(x²+2x+4)-1/(x-2)=(6x-x²-2x-4)/(x-2)(x²+2x+4)=
=(-x²+4x-4)/(x-2)(x²+2x+4)=-(x-2)²/(x-2)(x²+2x+4)=-(x-2)/(x²+2x+4)
2)(x-2)/(x²+2x+1)-(x-2)/(x²+2x+4)=(x-2)(x²+2x+4-x²-2x-1)/(x+1)²(x²+2x+4)=
=3/(x+1)²(x²+2x+4)