Question

упростите: $frac{x^2-25}{x+3} * frac{1}{x^2+5x} - frac{x+5}{x^2-3x}$

Answer 1

1)(x-5)(x+5)/(x+3)*1/x(x+5)=(x-5)/x(x+3)
2)(x-5)/x(x+3) -(x+5)/x(x-3)=(x²-5x-3x+15-x²-5x-3x-15)/x(x²-9)=
=-16x/x(x²-9)=16/(9-x²)