Question

Решите неравенства: а) 6х – 9 < 8х – 2; б) х/2 - (2х-3)/68 ≥ 1

Answer 1

6x-9<8x-2
6x-8x<-2+9
-2x<-7 |:(-2)
x>3,5

$frac{x}{2}- frac{2x-3}{68} geq 1$
$frac{x }{2} - frac{2x-3}{68} -1 geq 0$
$frac{34x-2x+3-68}{68} geq 0$
$frac{32x-65}{68} geq 0$
32x-65≥0
32x≥65
x≥65/32