Question

дано m (zncl2)=13,6 г найти m (hcl)-? v (zncl2)-?

Answer 1

2HCl+Zn=ZnCl2+H2
M(HCl) = 36,5
M(2HCl) = 73
M(ZnCl2) = 136
m(HCl) = 13,6*73/136 = 7,3(г)
V(ZnCl2) = 7,3*22,4/44,8 = 3,65(л)