Question

-sin (-π/2)-cos*(-3π/2)+cos(-π)-ctg(-3π/2) помогите решить

Answer 1

-sin (-π/2)-cos*(-3π/2)+cos(-π)-ctg(-3π/2)=sin π/2-cos( 3π/2)+cosπ+ctg( 3π/2)=
=1-0-1+0=0