Question

Упростить выражажение sin(x-pi)cos(x+2pi)sin(4pi-x)/sin(p/2+x)ctg(2pi-x)ctg(3pi/2+x)

Answer 1

[sin(x-π)*cos(x+2π)*sin(4π-x)]/[sin(π/2+x)*ctg(2π-x)*ctg(3π/2+x)]=
=[-sinx*cosx*(-sinx)]/[cosx*(-ctgx)*(-tgx)]=sin²x*cosx/(cosx*1)=sin²x