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x³ + (m - 1)x + m = 0
x(x² + m - 1) + m = 0
x(x² - 1) + m(x + 1) = 0
x(x - 1)(x + 1) + m(x + 1) = 0
(x + 1)(x(x - 1) + m) = 0 x = -1
x² - x + m = 0 D = b²-4ac = 1-4m
x₁ = (1+√(1-4m))/2
x₂ = (1-√(1-4m))/2
Ответ: {-1; (1+√(1-4m))/2; (1-√(1-4m))/2}
x(x² + m - 1) + m = 0
x(x² - 1) + m(x + 1) = 0
x(x - 1)(x + 1) + m(x + 1) = 0
(x + 1)(x(x - 1) + m) = 0 x = -1
x² - x + m = 0 D = b²-4ac = 1-4m
x₁ = (1+√(1-4m))/2
x₂ = (1-√(1-4m))/2
Ответ: {-1; (1+√(1-4m))/2; (1-√(1-4m))/2}
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