Question

Хеелп
(x+2)√-x²-10x+11≥0

Answer 1

(x+2)*√(-x²-10x+11)≥0
ОДЗ: -x²-10x+11≥0 |×(-1)
x²+10x-11≤0   D=144
x₁=1   x₂=-11   ⇒
(x-1)(x+11)≤0
-∞____+____-11____-____1____+____+∞
x∈[-11;1]
x+2≥0
x≥-2     ⇒
Ответ: x∈[-2;1].