Question

10х(5-(6+х))=х(х+3)-4х  помогите

Answer 1

10x(5-6-x)=x^2+3x-4x

50x-60x-10x^2=x^2+3x-4x

50x-60x-10x^2=x^2+3x-4x

x^2+10x^2+3x+60x-50x-4x=0

11x^2+9x=0

x(11x+9)=0

1)x1=0

2)11x=-9

    x2=-9/11

Answer 2

10х(5-(6+х))=х(х+3)-4х

10х(5-6-х)=х^2 + 3х - 4х

50х - 6-х - 1-х^2= х^2 + 3х - 4х

50х-60х-10х^2-х^2 - 3х +4х=0

-17х-10=0

-17х=10

х=-1,7