Question

доведи
3(a+1)+a<4(2+a);
(7p-1)(7p+1)>4d(d+2)

Answer 1

3(a+1)+a<4(2+a)
3a+3+a<8+4a
4a+4<8+4a
4a-4a<8-4
0<4

(7p-1)(7p+1)>4d(d+2)
49p^2-1>4d^2+8d
49p^2-4d^2-8d>1