Question

Решите Уравнения:
x^2+ 4x^2/(x+2)^2=5

Answer 1

5x^2/(x+2)^2=5
5x^2/(x+2)^2=5, x≠-2
5x^2=5(x+2)^2
x^2=(x+2)^2
x^2=x^2+4x+4
0=4x+4
-4x=4
x= -1, x≠ -2
ответ: x=-1

Answer 2

x^2+4x^2/(x+2)^2=5
x1=2
x2=-5/2-корень 15/2
x3=-1
x4=-5/2+корень 15/2
x1=-1
x2=2
x3=-2.5
x4=-2.5