Question

найдите значения выражения 1) 4/5+4/7×(7 11/12-5 7/9);
2) (4/5+4/7)×(7 11/12-5 7/9) Решить по действиям.

Answer 1

1) Начинаем со скобок 7 11/12-5 7/9 = 95/12 – 52/9 = 77/36

4/5+4/7×(7 11/12-5 7/9) = 4/5+4/7×77/36 = 4/5+11/9 = 91/45 = 2 1/45

2) скобки 7 11/12-5 7/9 = 95/12 – 52/9 = 77/36

(4/5+4/7)×(7 11/12-5 7/9) = (4/5+4/7) * 77/36 = 48/35 * 77/36 = 44/15 = 2 14/15