Question

Решить неравенство;
(1/2)^x+3>16

Answer 1

$left(frac12right)^{x+3} textgreater 16\2^{-(x+3)} textgreater 2^4\-(x+3) textgreater 4\-x-3 textgreater 4\-x textgreater 7\x textless -7$