Question

3^√128 = 4^2x

3^x^2-4x-05 = 81√3

Answer 1

3^√128=4^2Х
3^√2^7=2^4Х
2^(7/3)=2^4Х
(7/3)=4Х
(28/3)=Х

Х^2 - 4Х-0,5=9/2
Х^2-4Х-1/2-9/2=0
ХХ-4Х-5=0
Х=5;-1