Question

sin( (3π)/2 -2π) + 5sin(π-x) + 3=0

Answer 1

Решение
Sin( (3π)/2 -2π) + 5sin(π-x) + 3=0
Sin( (- π/2 ) + 5sin(π-x) + 3=0
- 1 + 5sinx + 3 = 0
sinx = - 2/5
x = (- 1)^n*arcsin(- 2/5) + πn, n ∈ Z
x = (- 1)^(n+1)*arcsin(2/5) + πn, n ∈ Z