Question

сократите дробь 2x^2-5 x+2/x^2-4x+4

Answer 1

(2х-1)(х-2)/(х-2)²=(2х-1)/(х+2)
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2х²-5х+2=2(х-1/2)(х-2)=(2х-1)(х-2)
D=25-16=9
x1=(5-3)/4=1/2
x2=(5+3)/4=2