Question

найти интеграл (6x^-3 +2sgrt(x) -19/x) dx

Answer 1

∫ (6x^-3 +2sgrt(x) -19/x) dx=[6x^(-3+1)]/(-2)+2[x^(1/2+1)]/(3/2)-19 ln x +C=
=-3/(x^2)+4x^(3/2)]/(3) -19 ln x +C